Awk to capture both variants of the commit ID

[andrew-glenn]

I had a nice awesome explaination but it didn't take, so..

TLDR:

• The current mechanism for identifying the submodule commit id for docs/boilerplate assumes the submodule has not been initialized. That's now a false assumption. This PR leverages awk to catch both use cases

❯ git submodule
-0ed73f22f2ea225fb62a8e20369423c77d41ba57 docs/boilerplate
❯ git submodule | grep docs/boilerplate | cut -d - -f 2 | awk '{print $1}'
0ed73f22f2ea225fb62a8e20369423c77d41ba57

❯ git submodule
 0ed73f22f2ea225fb62a8e20369423c77d41ba57 docs/boilerplate (heads/main)
❯ git submodule | grep docs/boilerplate | cut -d - -f 2 | awk '{print $1}'
0ed73f22f2ea225fb62a8e20369423c77d41ba57

Current Behavior

❯ git submodule
 0ed73f22f2ea225fb62a8e20369423c77d41ba57 docs/boilerplate (heads/main)
❯ git submodule | grep docs/boilerplate | cut -d - -f 2 | cut -f 1 -d " "

❯ git submodule
-0ed73f22f2ea225fb62a8e20369423c77d41ba57 docs/boilerplate
❯ git submodule | grep docs/boilerplate | cut -d - -f 2 | cut -f 1 -d " "
0ed73f22f2ea225fb62a8e20369423c77d41ba57