The file is empty. Empty files cannot be added to a repository.

[jda2004]

Write-CCFile -RepositoryName test-repo -BranchName master -FilePath /test/tst.tst -ParentCommitId abc123test -ProfileName test-profile

Write-CCFile : The file is empty. Empty files cannot be added to a repository.

I am continuously getting this error message even though the file is not empty. The goal is to write a file in codecommit using this syntax.

[matteo-prosperi]

Hello, I think you are missing the -FileContent parameter

[jda2004]

What do i put in -FileContent, the content of the file? I have a create table DDL in this file. Sould I just copy and paste that content within a single qoute?

[matteo-prosperi]

I think the simplest way to do this is

-FileContent ([System.IO.File]::ReadAllBytes('path to my file'))

-FilePath is the relative path to the file in the repository, not the path to a local file.

I am not familiar with these CodeCommit APIs but, if I read the docs correctly, this API will create one new commit for each file you add. In case you want to add multiple files in the same commit, New-CCCommit should do that.

[jda2004]

And............... it worked!!!.... thank you @matteo-prosperi You solved my 4 hours of digging in one shot!!!

[jda2004]

Hi @matteo-prosperi : I like to add little more information in my script. So this is the original syntax pattern from aws Write-CCFile -RepositoryName -BranchName -CommitMessage -Email -FileContent <Byte[]> -FileMode -FilePath -Name -ParentCommitId -Force I was thinking what content to go in FileMode and how to use '-Force' to force commit? Is the '-Name' going to be the destination file name?

[matteo-prosperi]

Hi, I can tell you that -Force is simply the PowerShell common parameter which will bypass the confirmation prompt of this cmdlet. -Force doesn't have any CodeCommit-specific use.

When it comes to the other parameters, have a look at the reference docs here. -Name appears to be "the name of the person adding or updating the file". -FileMode is one of the values of the FileModeTypeEnum (so you can do -FileMode NORMAL).

[jda2004]

One more :) @matteo-prosperi I am now thinking to put this syntax in an automation tool (WhereScape Red) template that will write the generated load script directly into the codecommit. In this case, I need to enable the FileContent to read a variable string. How to do that? For example: -FileContent ([System.IO.File]::ReadAllBytes('$Loadsql'))

[matteo-prosperi]

I am not sure I understand whether you have the file name in a variable or the content of the file in a variable. The former would be

-FileContent ([System.IO.File]::ReadAllBytes($FilePath))

the latter

-FileContent ([System.Text.Encoding]::UTF8.GetBytes($SomeText))

[jda2004]

Sorry for the confusion on the question, but you answered it with 'the latter' one. And it's working. Thanks for developing this one.