Open kawu001 opened 8 months ago
Hi kawu001,
demultiplexed <- read_csv('my_file.csv')
reads_1
or reads_2
columns - every row should contain two distinct FASTQ file paths for the forward and reverse reads.Hope that helps.
Hi Jemunro,
Thanks, it worked fine and was able to run haplotype filtering. However, I encountered another error.
seq_flt_tbl <- sequence_filter(seq_ann_tbl = seq_ann_tbl,
- sample_manifest = sample_manifest,
- marker_info = marker_info,
- output_dir = run_dir,
- vcf_output_dir = file.path(run_dir, 'vcf'),
- max_sm_miss = 1,
- max_marker_miss = 1,
- min_homo_rep = NULL,
- terminal_region_len = NULL
) Error in
auto_copy()
: !x
andy
must share the same src. ℹx
is a <tbl_df/tbl/data.frame> object. ℹy
isNULL
. ℹ Setcopy = TRUE
ify
can be copied to the same source asx
(may be slow). Runrlang::last_trace()
to see where the error occurred. rlang::last_trace() <error/rlang_error> Error inauto_copy()
: !x
andy
must share the same src. ℹx
is a <tbl_df/tbl/data.frame> object. ℹy
isNULL
. ℹ Setcopy = TRUE
ify
can be copied to the same source asx
(may be slow).Backtrace: ▆
- ├─AmpSeqR::sequence_filter(...)
- │ ├─base::suppressMessages(...)
- │ │ └─base::withCallingHandlers(...)
- │ └─seq_tbl_sameRef %>% ...
- ├─dplyr::left_join(...)
- └─dplyr:::left_join.data.frame(...)
└─dplyr::auto_copy(x, y, copy = copy) Run rlang::last_trace(drop = FALSE) to see 1 hidden frame. rlang::last_trace(drop = FALSE) <error/rlang_error> Error in
auto_copy()
: !x
andy
must share the same src. ℹx
is a <tbl_df/tbl/data.frame> object. ℹy
isNULL
. ℹ Setcopy = TRUE
ify
can be copied to the same source asx
(may be slow).Backtrace: ▆
- ├─AmpSeqR::sequence_filter(...)
- │ ├─base::suppressMessages(...)
- │ │ └─base::withCallingHandlers(...)
- │ └─seq_tbl_sameRef %>% ...
- ├─dplyr::left_join(...)
- └─dplyr:::left_join.data.frame(...)
- └─dplyr::auto_copy(x, y, copy = copy)
- └─rlang::abort(bullets).
Kindly look into this, Thanks.
This is where I think something might be wrong.
In the haplotype filtering process, the input file = seq_ann_tbl, in this table, the last two columns (ident, and ident_z) are numbers. But in my analysis, the result from the columns is one (ident) number and the other (ident_z) is NA. I think there should be a way to proceed with the NA. If the two are numbers, the haplotype filtering will run.
Hi, Thanks for the releasing a good package. I have the following issues;
How do you think I can solve these issues?
Thanks.