Method to [re]center a floating window?

[mxmilkiib]

I've tried bspc rule -a \* --one-shot node=focused center=on but it doesn't work. Is there a correct way to achieve this?

[danikron]

I think center=on is for setting the position of pseudo-tiled windows within their node. If you want to reposition a floating window you may need to use another tool, such as xdo, wmctrl or xdotool.

[baskerville]

I've tried bspc rule -a \* --one-shot node=focused center=on but it doesn't work.

You also need state=floating (node=focused is unnecessary).

I think center=on is for setting the position of pseudo-tiled windows within their node.

No it isn't. There's a global setting for this, called center_pseudo_tiled (cf. man bspc).

[mxmilkiib]

I realise now that no form of --one-shot rule is going to be a solution to this problem as they only affect windows spawned after rather than existing windows (or am I incorrect in that assumption?).

I ended up going with this kludge found via a search;

IFS='x' read screenWidth screenHeight < <(xdpyinfo | grep dimensions | grep -o '[0-9x]*' | head -n1)

width=$(xdotool getactivewindow getwindowgeometry --shell | head -4 | tail -1 | sed 's/[^0-9]*//')
height=$(xdotool getactivewindow getwindowgeometry --shell | head -5 | tail -1 | sed 's/[^0-9]*//')

newPosX=$((screenWidth/2-width/2-4))
newPosY=$((screenHeight/2-height/2-3))

xdotool getactivewindow windowmove "$newPosX" "$newPosY"

N.b. the -4 and -3 in the newPos calculations are added as otherwise the window does not align with a floating window of the same standard size created using a one-shot rule. Also, there is no guarantee of an exacting centre position with windows of varied size.

[baskerville]

I realise now that no form of --one-shot rule is going to be a solution to this problem as they only affect windows spawned after rather than existing windows (or am I incorrect in that assumption?).

This is correct: the rules don't affect existing windows.