Closed bastiatomic closed 3 years ago
Anzahl Möglichkeiten (Python-Code)
sum1, stop, removed_cards, index = 1, 45, -3,0
for stop in range(stop, 0, removed_cards): index +=1 sum1 = sum1 stop print(f'Depth {index}: {sum1:,} ({stop+removed_cards} ⬇️)')
shit posting
Anzahl Möglichkeiten (Python-Code)
every game has exactly 15 rounds
each round removes 3 cards from the game
21 points are needed for victory
all vulture cards are -15; therefore +36 mouse cards sufficient to win
sum1, stop, removed_cards, index = 1, 45, -3,0
for stop in range(stop, 0, removed_cards): index +=1 sum1 = sum1 stop print(f'Depth {index}: {sum1:,} ({stop+removed_cards} ⬇️)')