Problems determining SLon and DS

[jwingnut]

Thanks for making this available, several functions are already very useful, however to fully utilize the capabilities of this package I need to know how to determine SLon and DS.

I've done extensive searches but nothing has come up and both seem to be key arguments for some of the more advanced functions in this package.

How can I determine SLon and DS for a given site?

For example Kansas (39.0119° N, 98.4842° W).

[bbcrown]

Thanks for your interest. SLon is the standard time latitude, coming from the time zone time. DS is the daylight saving. As these two variables are based on the user-defined time zone, it would be a little tricky to fix them in the code. For example, some users some users might use a different time zone than the site's local time. But I agree that a default value would help. I will try to add a new argument as the time-zone, that way the user doesn't need to enter the SLon and DS. Thanks for your feedback.

For now, you can use this for your site in Kansas:

• Assume the site is in CT (UTC = -6), and every hour is equivalent of 15 degree standard longitudinal distance. Therefore, Slon is (-6)*15 = -90 and if you use daylight saving then DS = 60.

In the future release, I may probably get rid of these two and only have the time-zone input based on UTC, making the user responsible for daylight saving.

I hope this helps.

[bbcrown]

@jpwhitney please let me know if that was helpful.

[clgiebink]

@bnasr It was very helpful for me, thanks!