constant vector in normalize, method = range

[danielhorn]

Is this a bug? It happens for every constant vector.

normalize(c(0, 0), method = "range") [1] NaN NaN

From a mathematical point of view, it's correct. On the other hand - if normalizing i don't want to think about "uhm ... can my vector be constant?", I just want to use this function without additional prechecks. Perhaps a better behaviour would be to return the min/max/mean value of the given range?

[berndbischl]

Agree, so we want to normalize (c, c, ..., c) right?

Can you write down here how you want to transform this for all "method"s, please?

[danielhorn]

center: Everything is fine scale: Division by standard deviation is bad. I would say: If sd is 0, simply don't divide standardize: Same as scale range: return min / max or mean of given range interval. not sure which of these alternatives is the best

moreover, I just noticed:

is.matrix(normalize(c(1, 1, 1), method = "scale")) [1] TRUE is.matrix(normalize(c(1, 1, 1), method = "range")) [1] FALSE

[berndbischl]

Regarding last "error":

Do you really get that from the GH version? Because I fixed and tested this some time ago?

[berndbischl]

Regarding the real issue:

I agree. For range return the middle of the inverval. Also have on.constant = "stop" / "warn" / "quiet" For center your never warn or stop. Document and test this please.

[danielhorn]

Regarding error: You're right Regarding real issue: Done. Never warn / stop for center? This seems inconsistent to me, I would not treat center different.

PS: I don't have the permission to push to BBmisc?

[berndbischl]

Ok make it consistent.

You have push rights.

[danielhorn]

done with f8d2916a28e895bd44e4cf518450eb649327b577