Open ghost opened 1 year ago
1st bear = 1, 5, 5 2nd bear = 2, 2, 2 3rdf bear = 6, 6, 6
csum_1 = 1 , 6, 11 csum_2 = 2, 4, 6 csum_3 = 6, 12, 18
so csum_1[1] = csum_2[2] = csum_1[0]
Yes there is an logical error , hope the juniors will fix that
1st bear = 1, 5, 5 2nd bear = 2, 2, 2 3rdf bear = 6, 6, 6
csum_1 = 1 , 6, 11 csum_2 = 2, 4, 6 csum_3 = 6, 12, 18
so csum_1[1] = csum_2[2] = csum_1[0]
just checking same indices does not resolve the problem!