Closed biryu2205 closed 6 years ago
import java.util.Scanner; import java.util.regex.Pattern; import java.util.regex.PatternSyntaxException; public class Solution { public static void main(String[] args) { Scanner in = new Scanner(System.in); int testCases = Integer.parseInt(in.nextLine()); while (testCases > 0) { String pattern = in.nextLine(); try { Pattern.compile(pattern); System.out.println("Valid"); } catch (PatternSyntaxException e) { System.out.println("Invalid"); } testCases--; } } }