Open blueWind123731 opened 3 years ago
把所有的0移到左边,把所有的2移到右边,剩余的1即在中间。
var sortColors = function(nums) {
let left = 0,right = nums.length-1;
for(let i=0;i<=right;i++){
while(nums[i]===2&&i<right){
[nums[i],nums[right]]=[nums[right],nums[i]]
right--
}
while(nums[i]===0&&i>left){
[nums[left],nums[i]]=[nums[i],nums[left]]
left++
}
}
};
Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Follow up:
Could you solve this problem without using the library's sort function? Could you come up with a one-pass algorithm using only O(1) constant space?
Example 1:
Input: nums = [2,0,2,1,1,0] Output: [0,0,1,1,2,2] Example 2:
Input: nums = [2,0,1] Output: [0,1,2] Example 3:
Input: nums = [0] Output: [0] Example 4:
Input: nums = [1] Output: [1]
Constraints:
n == nums.length 1 <= n <= 300 nums[i] is 0, 1, or 2.