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blundar / analyze.exe

Binary file analysis tool
MIT License
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Precision = 4 (uint32) incorrect result #1

Open akudlacek opened 5 years ago

akudlacek commented 5 years ago

Given binary data 0x91 0x00 0x89 9x00 Motorola (Big endian) result is 2432698512 or 0x91000890 It should be 2432731392 or 0x91008900

At first glance it looks byte 3 did not get shifted correctly. Also the little endian result seems to be incorrect. I did not check Precision = 3 but Precision = 1,2 seem to be fine.

blundar commented 5 years ago

I didn't write this code. Submit a pull request if it really bothers you. :) -D

On Tue, May 28, 2019 at 5:43 PM akudlacek notifications@github.com wrote:

Given binary data 0x91 0x00 0x89 9x00 Motorola (Big endian) result is 2432698512 or 0x91000890 It should be 2432731392 or 0x91008900

At first glance it looks byte 3 did not get shifted correctly. Also the little endian result seems to be incorrect. I did not check Precision = 3 but Precision = 1,2 seem to be fine.

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