Open Aseyed opened 2 years ago
In your case, t+1=3 signer are needed to sign. So, if one is down, the signing can continue. If 2 are down, then whole signing process should stop.
In the case 2 of peers are down, should I stop the signing process? the process will be stocked? Or the process will handle it? In case one is down, the signing can continue. Is there any check or handling should I do?
I have a question about signing scenario: Assume t = 2 if there are 4 peers starting signing and in the middle, one of them went down. What should happen? Should the signing process be stopped, or should it continue? Is it necessary to use waitingfor function?