boakley
commented
10 years ago A new option has been added, --interface, which lets you supply which interface(s) it listens on (eg: python -m rfhub --interface 0.0.0.0). That will be available in the next version which will hopefully be ready sometime this week.
On Mon, Aug 11, 2014 at 4:22 AM, Tatu Aalto notifications@github.com wrote:
By default rfhub starts on localhost and is not served to outside world. It would be real handy that if there would be configuration parameter set the host.
For a workaround I did change the app.py line 36, from self.app.run(port=self.opts.port, debug=self.opts.debug) to self.app.run(host="0.0.0.0", port=self.opts.port, debug=self.opts.debug)
— Reply to this email directly or view it on GitHub https://github.com/boakley/robotframework-hub/issues/27.
aaltat
By default rfhub starts on localhost and is not served to outside world. It would be real handy that if there would be configuration parameter set the host.
For a workaround I did change the app.py line 36, from self.app.run(port=self.opts.port, debug=self.opts.debug) to self.app.run(host="0.0.0.0", port=self.opts.port, debug=self.opts.debug)