Closed Nothing4You closed 9 years ago
Yes and no.
Yes it does if you use Boon.toJson and/or Boon.toPrettyJson.
Those are quick and easy. They do use fields. They will use the getters if they don't find the field.
But it does support getters if you use the JsonBuilder gak to configure serialization.
I will search doc for instructions and if I can't find it then I will write it up.
It supports. I am 99.999 percent sure.
On Thu, Feb 19, 2015 at 5:42 AM, Richard Schwab notifications@github.com wrote:
Currently it seems like boon just completely ignores possibly available getters for properties. This prevents lazy loading of information, e.g. initializing an object with an id and loading info like name later when it's required to reduce load.
— Reply to this email directly or view it on GitHub https://github.com/boonproject/boon/issues/303.
Rick Hightower (415) 968-9037 Profile http://www.google.com/profiles/RichardHightower
Thanks, this works for me:
final JsonSerializer serializer = new JsonSerializerFactory().usePropertiesFirst().create();
response.getWriter().println(serializer.serialize(result));
The important part is .usePropertiesFirst()
.
Found a reference for the factory here and looked at the methods of the factory.
However, is there any way I could get pretty JSON from this? Would I have to parseJson this and then toPrettyJson it?
final JsonSerializer serializer = new JsonSerializerFactory().usePropertiesFirst().create();
response.getWriter().println(Boon.toPrettyJson(Boon.fromJson(serializer.serialize(result).toString())));
works, but it'd be nice if I wouldn't have to parse and serialize it twice.
Good work.
Currently it seems like boon just completely ignores possibly available getters for properties. This prevents lazy loading of information, e.g. initializing an object with an id and loading info like name later when it's required to reduce load.