Weird endian_buffer assignment from T when the conversion is explicit

[viboes]

Wiven that the conversion from T is explicit, the assignment shouldn't be allowed.

      explicit endian_buffer(T v) noexcept;

      endian_buffer& operator=(T v) noexcept;

Either the conversion is implicit and the assignment is an optimization, or the conversion is explicit and the assignment should be removed.

[viboes]

Note that endian_arithmetic is already implicitly constructible from T. Why endian_arithmetic implicitly constructible from T while endian_buffer is not?

[pdimov]

This all seems to be by design. endian_buffer has no implicit conversions, endian_arithmetic does.