Closed Joelgranados closed 9 years ago
Such unexpected matter, as it's done, usually causes lots of trouble in manipulation of large data.
This is no longer the case. There is now a 0 when the image is visible. It is zero because the last pot is a marker. Additionally, it may also be a NaN when the algorithm cannot detect what is there.
Such unexpected matter, as it's done, usually causes lots of trouble in manipulation of large data.