What steps will reproduce the problem?
1. The comment for Open() says "Any existing file will be overwritten."
What is the expected output? What do you see instead?
If the given path already exists Open() will fail.
Original issue reported on code.google.com by rjogr...@google.com on 21 Apr 2014 at 5:48
Original issue reported on code.google.com by
rjogr...@google.com
on 21 Apr 2014 at 5:48