carloscn
commented
1 year ago Analysis
pub fn largest_odd_number(num: &str) -> String
{
if num.len() < 1 {
return String::new();
}
let mut num_vec:Vec<char> = num.chars().collect();
while num_vec.len() != 0 {
if num_vec[num_vec.len() - 1] as u8 & 1 == 1 {
break;
}
num_vec.remove(num_vec.len() - 1);
}
let ret:String = num_vec.into_iter().collect();
return ret;
}
Description
You are given a string num, representing a large integer. Return the largest-valued odd integer (as a string) that is a non-empty substring of num, or an empty string "" if no odd integer exists.
A substring is a contiguous sequence of characters within a string.
Example 1:
Input: num = "52" Output: "5" Explanation: The only non-empty substrings are "5", "2", and "52". "5" is the only odd number.
Example 2:
Input: num = "4206" Output: "" Explanation: There are no odd numbers in "4206".
Example 3:
Input: num = "35427" Output: "35427" Explanation: "35427" is already an odd number.
Constraints:
1 <= num.length <= 105 num only consists of digits and does not contain any leading zeros.