carloscn
commented
1 year ago Description
int32_t smallest_equal(int32_t* nums, size_t len, int32_t *index)
{
int32_t ret = 0;
UTILS_CHECK_PTR(nums);
UTILS_CHECK_PTR(index);
UTILS_CHECK_LEN(len);
*index = -1;
for (size_t i = 0; i < len; i ++) {
if (i % 10 == nums[i]) {
*index = (int32_t) i;
goto finish;
}
}
finish:
return ret;
}
Description
Given a 0-indexed integer array nums, return the smallest index i of nums such that i mod 10 == nums[i], or -1 if such index does not exist.
x mod y denotes the remainder when x is divided by y.
Example 1:
Input: nums = [0,1,2] Output: 0 Explanation: i=0: 0 mod 10 = 0 == nums[0]. i=1: 1 mod 10 = 1 == nums[1]. i=2: 2 mod 10 = 2 == nums[2]. All indices have i mod 10 == nums[i], so we return the smallest index 0.
Example 2:
Input: nums = [4,3,2,1] Output: 2 Explanation: i=0: 0 mod 10 = 0 != nums[0]. i=1: 1 mod 10 = 1 != nums[1]. i=2: 2 mod 10 = 2 == nums[2]. i=3: 3 mod 10 = 3 != nums[3]. 2 is the only index which has i mod 10 == nums[i].
Example 3:
Input: nums = [1,2,3,4,5,6,7,8,9,0] Output: -1 Explanation: No index satisfies i mod 10 == nums[i].
Constraints:
1 <= nums.length <= 100 0 <= nums[i] <= 9