Open carloscn opened 1 year ago
static int32_t min_bit_flips(int32_t start, int32_t goal)
{
int32_t ret = 0;
for (size_t i = 0; i < sizeof(int32_t) * 8; i ++) {
ret += ((start >> i) & 0x1) != \
((goal >> i) & 0x1);
}
finish:
return ret;
}
Description
A bit flip of a number x is choosing a bit in the binary representation of x and flipping it from either 0 to 1 or 1 to 0.
For example, for x = 7, the binary representation is 111 and we may choose any bit (including any leading zeros not shown) and flip it. We can flip the first bit from the right to get 110, flip the second bit from the right to get 101, flip the fifth bit from the right (a leading zero) to get 10111, etc. Given two integers start and goal, return the minimum number of bit flips to convert start to goal.
Example 1:
Input: start = 10, goal = 7 Output: 3 Explanation: The binary representation of 10 and 7 are 1010 and 0111 respectively. We can convert 10 to 7 in 3 steps:
Example 2:
Input: start = 3, goal = 4 Output: 3 Explanation: The binary representation of 3 and 4 are 011 and 100 respectively. We can convert 3 to 4 in 3 steps:
Constraints:
0 <= start, goal <= 109