carloscn / structstudy

Leetcode daily trainning by using C/C++/RUST programming.
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leetcode2220: Minimum Bit Flips to Convert Number #361

Open carloscn opened 1 year ago

carloscn commented 1 year ago

Description

A bit flip of a number x is choosing a bit in the binary representation of x and flipping it from either 0 to 1 or 1 to 0.

For example, for x = 7, the binary representation is 111 and we may choose any bit (including any leading zeros not shown) and flip it. We can flip the first bit from the right to get 110, flip the second bit from the right to get 101, flip the fifth bit from the right (a leading zero) to get 10111, etc. Given two integers start and goal, return the minimum number of bit flips to convert start to goal.

Example 1:

Input: start = 10, goal = 7 Output: 3 Explanation: The binary representation of 10 and 7 are 1010 and 0111 respectively. We can convert 10 to 7 in 3 steps:

Example 2:

Input: start = 3, goal = 4 Output: 3 Explanation: The binary representation of 3 and 4 are 011 and 100 respectively. We can convert 3 to 4 in 3 steps:

Constraints:

0 <= start, goal <= 109

carloscn commented 1 year ago

Analysis

static int32_t min_bit_flips(int32_t start, int32_t goal)
{
    int32_t ret = 0;

    for (size_t i = 0; i < sizeof(int32_t) * 8; i ++) {
        ret += ((start >> i) & 0x1) != \
               ((goal >> i) & 0x1);
    }

finish:
    return ret;
}
carloscn commented 1 year ago

Code

https://review.gerrithub.io/c/carloscn/structstudy/+/1169879 https://github.com/carloscn/structstudy/commit/d7cc355de94cce8aaddd1fc2135b2cb35b838386