carloscn
commented
1 year ago Analysis
pub fn merge_similar_items(items1: Vec<Vec<i32>>, items2: Vec<Vec<i32>>) -> Vec<Vec<i32>>
{
let mut ret:Vec<Vec<i32>> = vec![];
if items1.len() < 1 && items2.len() < 1 {
return ret;
}
let mut tv = items1.clone();
tv.append(&mut items2.clone());
tv.push(vec![i32::MAX, 0]);
tv.sort();
let mut i:usize = 0;
while i < tv.len() - 1 {
let mut e: Vec<i32> = vec![0; 2];
e[0] = tv[i][0];
if tv[i][0] == tv[i + 1][0] {
e[1] = tv[i][1] + tv[i + 1][1];
i += 2;
} else {
e[1] = tv[i][1];
i += 1;
}
ret.push(e);
}
return ret;
}
Description
You are given two 2D integer arrays, items1 and items2, representing two sets of items. Each array items has the following properties:
items[i] = [valuei, weighti] where valuei represents the value and weighti represents the weight of the ith item. The value of each item in items is unique. Return a 2D integer array ret where ret[i] = [valuei, weighti], with weighti being the sum of weights of all items with value valuei.
Note: ret should be returned in ascending order by value.
Example 1:
Input: items1 = [[1,1],[4,5],[3,8]], items2 = [[3,1],[1,5]] Output: [[1,6],[3,9],[4,5]] Explanation: The item with value = 1 occurs in items1 with weight = 1 and in items2 with weight = 5, total weight = 1 + 5 = 6. The item with value = 3 occurs in items1 with weight = 8 and in items2 with weight = 1, total weight = 8 + 1 = 9. The item with value = 4 occurs in items1 with weight = 5, total weight = 5.
Therefore, we return [[1,6],[3,9],[4,5]].
Example 2:
Input: items1 = [[1,1],[3,2],[2,3]], items2 = [[2,1],[3,2],[1,3]] Output: [[1,4],[2,4],[3,4]] Explanation: The item with value = 1 occurs in items1 with weight = 1 and in items2 with weight = 3, total weight = 1 + 3 = 4. The item with value = 2 occurs in items1 with weight = 3 and in items2 with weight = 1, total weight = 3 + 1 = 4. The item with value = 3 occurs in items1 with weight = 2 and in items2 with weight = 2, total weight = 2 + 2 = 4. Therefore, we return [[1,4],[2,4],[3,4]].
Example 3:
Input: items1 = [[1,3],[2,2]], items2 = [[7,1],[2,2],[1,4]] Output: [[1,7],[2,4],[7,1]] Explanation: The item with value = 1 occurs in items1 with weight = 3 and in items2 with weight = 4, total weight = 3 + 4 = 7. The item with value = 2 occurs in items1 with weight = 2 and in items2 with weight = 2, total weight = 2 + 2 = 4. The item with value = 7 occurs in items2 with weight = 1, total weight = 1. Therefore, we return [[1,7],[2,4],[7,1]].
Constraints:
1 <= items1.length, items2.length <= 1000 items1[i].length == items2[i].length == 2 1 <= valuei, weighti <= 1000 Each valuei in items1 is unique. Each valuei in items2 is unique.