Open carloscn opened 12 months ago
pub fn sum_of_multiples(n: i32) -> i32
{
let mut ret = 0;
if n == 0 {
return ret;
}
for i in 1..(n + 1) {
if (i % 3 == 0) || (i % 5 == 0) || (i % 7 == 0) {
ret += i;
}
}
return ret;
}
Description
Given a positive integer n, find the sum of all integers in the range [1, n] inclusive that are divisible by 3, 5, or 7.
Return an integer denoting the sum of all numbers in the given range satisfying the constraint.
Example 1:
Input: n = 7 Output: 21 Explanation: Numbers in the range [1, 7] that are divisible by 3, 5, or 7 are 3, 5, 6, 7. The sum of these numbers is 21.
Example 2:
Input: n = 10 Output: 40 Explanation: Numbers in the range [1, 10] that are divisible by 3, 5, or 7 are 3, 5, 6, 7, 9, 10. The sum of these numbers is 40.
Example 3:
Input: n = 9 Output: 30 Explanation: Numbers in the range [1, 9] that are divisible by 3, 5, or 7 are 3, 5, 6, 7, 9. The sum of these numbers is 30.
Constraints:
1 <= n <= 103