cdelker / ziamath

MIT License
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\uparrow height #80

Open pozitron57 opened 17 hours ago

pozitron57 commented 17 hours ago

\uparrow, \downarrow has the height of the line (version 0.11).

$v=\sqrt{\dfrac{GM}{r\downarrow}} \Rightarrow v \uparrow$

XeLaTeX:

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Ziamath:

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pozitron57 commented 16 hours ago

Probably the same issue:

$\langle u \rangle = \sqrt{\dfrac{\langle u_1 \rangle^2+\langle u_2 \rangle^2}{2}}$

image