Open clemens-unterkofler opened 7 months ago
When an interrupt calls EmulOp, which calls an Execute68kTrap, which does an m68k_execute, this code execution will again run into other interrupts, ignoring the original interrupt mask. I believe this to be a bug.
When an interrupt calls EmulOp, which calls an Execute68kTrap, which does an m68k_execute, this code execution will again run into other interrupts, ignoring the original interrupt mask. I believe this to be a bug.