Closed quintesse closed 9 years ago
Instead print(1 % 0) gives NaN.0
print(1 % 0)
NaN.0
That's the problem with optimizing to native operators...
But it works for 1 / 0 doesn't it? So aren't checking for that special case or how does that work?
1 / 0
Instead
print(1 % 0)
givesNaN.0