Open mazeau opened 5 years ago
Great! My thoughts are: 1st rxn, inserting 3-4 between 1-2: probably going to have a high barrier? It should happen, but probably not my first choice. 2cd rxn, dangling double falls flat: very important! I would do this one first. It touches on the other thread we have on pi- vs di-sigma. 3rd + 4th rxns: I think I'm missing something here, but it looks like it won't satisfy the octet rule for 2 in rxn3 or 3 in rxn4? Let's say that 1-2=3 are allyl, so that we have surface propene (X-CH2-CH=CH2). in rxn3, we have X-CH2-CH-CH2-X, so C2 is short one bond. Ditto C3 in the other case. fifth rxn: if 2 is H, then yes, could be important. If 2 is some other functional group, probably less so. I would probably make this my number 2 choice. However, I would make one big difference. Radicals on surfaces aren't really much of a thing, definitely not for the bonding atom. I would remove the radical from X-1* in the product and instead increase the bond order, X=1. 6th rxn: seems less likely. I guess the idea is to have addition/isomerization/elimination, and not a single abstract step? probably hard to find decent data to parameterize that one.
for the dangling double falls flat, I don't think that follows the octet rule either. I think it would have to be something like this:
1=2 3-1-2
| + 3 <=> | |
X X X X
where 3 would be a hydrogen or something?
I edited your original post above, to add some numbers, as I was getting confused by the counting. Now maybe the other comments need editing so they correspond . Also, reading Franklin's first comment on reaction 1 had me (or him) confused if 1 is itself an X (as I now drew) or was adsorbed to an X.
Thanks, that helps. For Reaction 2, I was thinking of two different cases:
1=2 1-2
| + <=> || |
X X X X
which, with the bond order increase, does preserve the octet rule. Then, additionally, the pi- to -di-sigma would be:
(1=2) 1-2
: + <=> | |
X X X X
where (1=2)
indicates a vdW structure
I don't like those as much. My original meaning behind that one was to get benzene fully adsorbed to the surface and then hydrogenated and desorbed.
Look for things by one of Norskov's students. An oral talk at AIChE a year or two ago. Probably published by now.
I can't figure out how to open up an issue on the RMG-database so I just put it here instead
Now that Eley-Rideal is a little added, we came across some other families to potentially add to help us deal with bidentate/multidentate species.
Have just added:
1 EleyRideal_H_addition_multiple_bond
where
4=3
can be a double, triple, or quadruple bond, and 2 is an H atom.Some potential families to add are:
2
where
2
is a radical, probably an H.Would be good to have
3
where 3 is a radical, probably a hydrogen or something?
Probably less likely than number 2, above. If you had that starting point, it would probably just go like this instead:
4
where
2=3
can be a double or triple bond. 4 is probably an HProbably a similar story to number 3. It's overall 3rd order (two surface sites and a gas phase species)
5
where
2=3
can be a double or triple bond. 4 is probably an HProbably a similar story to number 3. It's overall 3rd order (two surface sites and a gas phase species)
6
3 is a radical, abstracts 2. eg. 1 is CH2, 3 is CH3, 2 is H, you get methane and =CH2
Seems reasonable. Not unlike H abstraction in gas phase.
Would be good to have
7
Not going to work. because you have to break a double bond (1=2), and 2 ends up unhappy.