Open drakenstar opened 1 year ago
Ok I dug into this and I think found the reason for this output. wordwrap.String
called by Style.Render
will not output spaces at the end of a line unless it finds a \n character before the limit. For example:
s := wordwrap.String("test test ", 6)
fmt.Print(s)
// "test\ntest"
s := wordwrap.String("test \ntest ", 6)
fmt.Print(s)
// "test \ntest"
This is arguably surprising from their end, however lipgloss could workaround this by trimming whitespace this output if it is not styled by seeking backwards per line for \x1b[0m
and trimming spaces after it.
I'm happy to PR this if there's agreement it should be fixed.
Okay yep, this is indeed a bug. I suspect the solution may be may complex than this, though we'll need to look into it further before we can have an opinion on the fix.
Here's a centered use case to further illustrate the issue.
package main
import (
"fmt"
"github.com/charmbracelet/lipgloss"
)
func main() {
redStyle := lipgloss.NewStyle().
Background(lipgloss.Color("#FF0000")).
Width(10)
greenStyle := lipgloss.NewStyle().
Background(lipgloss.Color("#00FF00")).
Width(10)
outerStyle := lipgloss.NewStyle().
Width(40).
Background(lipgloss.Color("#0000FF"))
fmt.Println(outerStyle.Render(lipgloss.JoinHorizontal(lipgloss.Center,
greenStyle.Render("left text"),
redStyle.Render("multi\nline\ncenter\ntext\nwow"),
greenStyle.Render("right text"),
)))
}
I've worked around this locally doing as I described above and trimming space characters from the end of a line if they are immediately preceded by a reset sequence.
However there's another harder case that workaround still doesn't solve:
redStyle := lipgloss.NewStyle().
Background(lipgloss.Color("#FF0000")).
Width(10)
greenStyle := lipgloss.NewStyle().
Background(lipgloss.Color("#00FF00")).
Width(10)
outerStyle := lipgloss.NewStyle().
Width(40).
Background(lipgloss.Color("#0000FF"))
fmt.Println(outerStyle.Render(lipgloss.JoinHorizontal(0,
redStyle.Render("multi\nline"),
greenStyle.Render("left text"),
redStyle.Render("multi\nline"),
)))
Resulting in:
A more complete solve for this is probably inspecting each line for segments that have no styling any applying the current style to them.
For now, I'd probably workaround this by simply placing the short column (or all columns) over the appropriate background color with lipgloss.Place
(see example and docs).
Here’s how I'd fix my above example (in a real scenario I'd abstract the Place
stuff and generalize it to work for all columns):
package main
import (
"fmt"
"github.com/charmbracelet/lipgloss"
)
func main() {
const blue = lipgloss.Color("#0000FF")
redStyle := lipgloss.NewStyle().
Background(lipgloss.Color("#FF0000")).
Width(10)
greenStyle := lipgloss.NewStyle().
Background(lipgloss.Color("#00FF00")).
Width(10)
outerStyle := lipgloss.NewStyle().
Width(40).
Background(blue)
leftContent := greenStyle.Render("left text")
middleContent := redStyle.Render("multi\nline\ncenter\ntext\nwow")
rightContent := greenStyle.Render("right text")
fmt.Println(outerStyle.Render(
lipgloss.JoinHorizontal(
lipgloss.Center,
leftContent,
middleContent,
lipgloss.Place(
lipgloss.Width(rightContent), // width
lipgloss.Height(middleContent), // height
lipgloss.Left, // x
lipgloss.Center, // y
rightContent, // content
lipgloss.WithWhitespaceBackground(blue), // background
),
)))
}
Output:
Describe the bug When rendering strings with backgrounds already applied, the background from our rendering style has issues. In this test case, I've joined 3 other strings using
JoinHorizontal
that each have their own background. Note the missing background beneath the "right text" section:Note the area beneath "right text" that does not have a background style applied.
Setup
Source Code Simple reproduce:
Expected behavior In this case I would have expected the blue background from
style3
to be rendered in all spaces where there is no background applied.