could not join a group

[vineethsreekumar]

1. Is the bug present in the demo Chat SDK project? - yes

2. What modifications have you made to the Chat SDK? - a user could not join a group thread

3. iOS Version? Device or simulator? iphone 13 pro max

4. Steps taken to reproduce the problem: let grouptthread = BChatSDK.db().thread(forEntityID: "-N0adpBTTN_xMSYNL2f0") use join function in chatSDK.thread().join(groupthread)

5. Expected result: the current user should be joined to the group thread

6. Actual result: groupthread is nil

7. Comments: Can we add a user to a group thread in this way or do you have any other way to join a pivate group @bensmiley @denniszxxc @angelolloqui @ealeksandrov

[bensmiley]

The correct code would be something like this:

if let thread = BChatSDK.db().fetchOrCreateEntity(withID: "thread-id", withType: bThreadType) as? PThread {
    if(BChatSDK.thread().canJoin(thread)) {
        BChatSDK.thread().join(thread)
    }
}

But there is no guarantee the user can join. In general, users need to be invited by the thread owner.

[vineethsreekumar]

How a thread owner can invite another user?

[vineethsreekumar]

How a thread owner can invite another user?

@bensmiley

[vineethsreekumar]

@bensmiley we already tried fetchOrCreateEntity the thread doesnt have any meta and other data. seems we need to do invite from creator side. How we can invite a user with chatSDK ?

[abhi-9605]

How we can invite a user with chat SDK android? ( Using firebase real-time database ) @bensmiley

[bensmiley]

You can add users like this:

iOS:

BChatSDK.thread().addUsers([user1, user2], to: thread)

Android:

ChatSDK.thread().addUsersToThread(thread, user1, user2).subscribe()

[vineethsreekumar]

@bensmiley BChatSDK.thread().addUsers this will add the user right. what we need is invite a user via link and clicking on the link user should be able to join the group

[bensmiley]

@vineethsreekumar there is no built in function to do what you want. If you want that functionality you would need to build it yourself.