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chembl / chembl_webresource_client

Official Python client for accessing ChEMBL API
https://www.ebi.ac.uk/chembl/api/data/docs
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simplejson.scanner.JSONDecodeError: Expecting value: line 1 column 1 (char 0) #87

Closed srp6996 closed 2 years ago

srp6996 commented 4 years ago

I was tired your example code import requests url = 'https://www.ebi.ac.uk/chembl/api/utils/spore' r = requests.get(url) print (r.status_code) print (r.ok) print (r.json())

which i got output properly but when am using for youtube links am getting error

import requests url = 'https://www.youtube.com/watch?v=wHiUlFH8AAQ' r = requests.get(url) print (r.status_code) print (r.ok) print r.json()

Output what i got: 200 True Traceback (most recent call last): File "test.py", line 6, in print (r.json()) File "/home/user/.local/lib/python3.6/site-packages/requests/models.py", line 898, in json return complexjson.loads(self.text, **kwargs) File "/usr/lib/python3/dist-packages/simplejson/init.py", line 518, in loads return _default_decoder.decode(s) File "/usr/lib/python3/dist-packages/simplejson/decoder.py", line 370, in decode obj, end = self.raw_decode(s) File "/usr/lib/python3/dist-packages/simplejson/decoder.py", line 400, in raw_decode return self.scan_once(s, idx=_w(s, idx).end()) simplejson.errors.JSONDecodeError: Expecting value: line 1 column 1 (char 0)