Closed chengchengxu15 closed 3 years ago
Note:
It takes time for me to debug: +1 -1 ...
class Solution:
"""
@param n: a integer
@return: return a string
"""
def convertToTitle(self, n):
# write your code here
dict = {1:"A",
2:"B",
3:"C",
4:"D",
5:"E",
6:"F",
7:"G",
8:"H",
9:"I",
10:"J",
11:"K",
12:"L",
13:"M",
14:"N",
15:"O",
16:"P",
17:"Q",
18:"R",
19:"S",
20:"T",
21:"U",
22:"V",
23:"W",
24:"X",
25:"Y",
0:"Z",
26:"Z"
}
if n <= 0:
return ""
else:
result = ""
q = 1
while q > 0:
q = (n-1)//26
m = (n-1)%26
n = q
result = dict[(m+1)] + result
return result
class Solution:
"""
@param n: a integer
@return: return a string
"""
def convertToTitle(self, n):
# write your code here
string = "ZABCDEFGHIJKLMNOPQRSTUVWXYZ"
if n <= 0:
return ""
else:
result = ""
q = 1
while q > 0:
q = (n-1)//26
m = (n-1)%26
n = q
result = string[m+1] + result
return result
class Solution:
"""
@param n: a integer
@return: return a string
"""
def convertToTitle(self, n):
# write your code here
result = []
while n > 0:
c = chr((n - 1) % 26 + ord('A'))
result.append(c)
n = (n - 1) // 26
return ''.join(result[::-1])
lentcode: https://www.lintcode.com/problem/1350/?_from=collection&fromId=29 leetcode: https://leetcode.com/problems/excel-sheet-column-title/
Description Given a positive integer, return its corresponding column title as appear in an Excel sheet.
1 -> A 2 -> B 3 -> C ... 26 -> Z 27 -> AA 28 -> AB
first time 07/12/2021