Open barrym95838 opened 3 years ago
If we're only concerned about the Z flag, we could shave two bytes and a few cycles here, right?:
peq lda stackh,x ; [4] eor tos+1 ; [3] bne peq99 ; [2*] lda stackl,x ; [4] eor tos ; [3] peq99 rts ; [6] ; Z flag is (TOS = 2OS)
If we're only concerned about the Z flag, we could shave two bytes and a few cycles here, right?: