assignop on string with char concats char code instead of char

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assignop on string with char concats char code instead of char #481

Closed lgrignon closed 6 years ago

lgrignon commented 6 years ago

String ok = "";
ok = ok + (char)(97);
console.log(ok); //works, prints 'a'
String msg = "";
msg += (char)(97);
console.log(msg); //doesn't work, += results in 97