modp_numtoa_test failed on mips (big-endian) with the following message:
modp_numtoa_test.c ............ASSERTION FAILED: modp_numtoa_test.c:495 10000000 != 00000001
There is no need to separate the code for big and little endian. The bitwise operators abstract away the endianness. The >> operator always shifts the bits towards the least significant digit. Endianness matters when dealing with individual bytes in a larger structure.
I have tested this PR successfully on mips, mipsel and i386.
client9
commented
8 years ago
modp_numtoa_test failed on mips (big-endian) with the following message:
modp_numtoa_test.c ............ASSERTION FAILED: modp_numtoa_test.c:495 10000000 != 00000001There is no need to separate the code for big and little endian. The bitwise operators abstract away the endianness. The >> operator always shifts the bits towards the least significant digit. Endianness matters when dealing with individual bytes in a larger structure.
I have tested this PR successfully on mips, mipsel and i386.