pykeyvi segfault 11

[lexplua]

sample code

compiler = pykeyvi.StringDictionaryCompiler()
compiler.Add('a', 'b')
compiler.WriteToFile('dump1.kv')

Stacktrace

keyvi::dictionary::DictionaryCompiler<keyvi::dictionary::fsa::internal::SparseArrayPersistence<unsigned short>, keyvi::dictionary::fsa::internal::StringValueStore, keyvi::dictionary::sort::TpieSorter<keyvi::dictionary::sort::key_value_pair<std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >, keyvi::dictionary::fsa::ValueHandle> > >::WriteToFile<std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> > >(std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >) + 243
1   pykeyvi.so                      0x000000010d0aef1b __pyx_pw_7pykeyvi_24StringDictionaryCompiler_15WriteToFile(_object*, _object*) + 411

OSX, Python 2.7/3.6

[hendrikmuhs]

You miss the Compile step, after Add:

compiler = pykeyvi.StringDictionaryCompiler()
compiler.Add('a', 'b')
compiler.Compile()
compiler.WriteToFile('dump1.kv')

For your code WriteToFile should throw an exception. Looks like that does not happen?

I will check it. Maybe the python binding does not handle it correctly.