It should be
} else if($ftype=='F')
not
} else if($ftype='F')
What steps will reproduce the problem?
1.
2.
3.
What is the expected output? What do you see instead?
What version of the product are you using? On what operating system?
Please provide any additional information below.
Original issue reported on code.google.com by yoann.pa...@gmail.com on 23 Apr 2011 at 1:10
Original issue reported on code.google.com by
yoann.pa...@gmail.com
on 23 Apr 2011 at 1:10