Bug: z.output makes all properties optional

[MickL]

Using z.output, ALL properties optional. E.g. the following should throw a TypeScript error that count is required but it does not:

export const myMsgSchema = z.object({
  message: z.string(),
  count: z.number().positive(),
});

export type MyMsg = z.output<typeof myMsgschema>;

const msg: MyMsg = {
  message: 'hello';
}

[BrendanC23]

Are you using TypeScript's strict mode? See the docs.

Also, your example has some small typos that might be causing issues.

export const myMsgSchema = z.object({
    message: z.string(),
    count: z.number().positive(),
});

export type MyMsg = z.output<typeof myMsgSchema>; // Fixed capitalization

const msg: MyMsg = {
    message: "hello", // Changed to comma
};

With strict mode, your example is giving me an error.

[MickL]

The typos were because I created the example out of my code.

strict mode "fixed" it, thanks.