where \\\", printed as \", is exactly the content of echo "\"".
However, in bash(version 4.3.48), the output of echo "\"" is just ".
As mentioned in IEEE Std 1003.1™ - 2017, Vol. 3: Shell and Utilities, Issue 7, (Is it out of date?)
2.6.7 Quote Removal
The quote characters (<backslash>, single-quote, and double-quote) that were present in the
original word shall be removed unless they have themselves been quoted.
Is \<backslash> removal under plan, or left to the conversion stage from concrete syntax tree to abstract syntax tree?
Below is a test case, which is thought good https://github.com/colis-anr/morbig/blob/2441635d3836135294a2d5c2d89f149f09c368b4/tests/good/2.6-word-expansions/2.6.3-command-substitutions/backslash-in-nested-subshells.sh#L3
Its corresponding expected CST, inside
WordDoubleQuoted
, is https://github.com/colis-anr/morbig/blob/2441635d3836135294a2d5c2d89f149f09c368b4/tests/good/2.6-word-expansions/2.6.3-command-substitutions/backslash-in-nested-subshells.sh.expected#L41where
\\\"
, printed as\"
, is exactly the content ofecho "\""
. However, in bash(version 4.3.48), the output ofecho "\""
is just"
.As mentioned in IEEE Std 1003.1™ - 2017, Vol. 3: Shell and Utilities, Issue 7, (Is it out of date?)
Is \<backslash> removal under plan, or left to the conversion stage from concrete syntax tree to abstract syntax tree?
BTW, thanks for your brilliant work!