comp-think / 2021-2022

The GitHub repository containing all the material related to the Computational Thinking and Programming course of the Digital Humanities and Digital Knowledge degree at the University of Bologna (a.a. 2021/2022).
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Lecture "Brute-force argorithms", exercise 3 #19

Open essepuntato opened 2 years ago

essepuntato commented 2 years ago

Write in Python the function def my_enumerate(input_list), which behaves like the built-in function enumerate() introduced in Section "Linear search" and returns a proper list, and accompany the function with the related test case. It is not possible to use the built-in function enumerate() in the implementation.

ManuSrivastava1 commented 2 years ago

Here is my version of enumerate function.

def my_enumerate(input_list):
    x = len(input_list)
    y= 0
    output_list = []
    while y <= x-1:
        output_tuple = (y,input_list[y])
        output_list.append(output_tuple)
        y += 1
    return output_list

Here is the visualization of how the function works

Below is the test code for the above written algorithm -

def test_my_enumerate(input_list,output_list,expected):
    n=0
    while n < len(input_list):
        item_from_list = output_list[n]
        if item_from_list[1]==input_list[n] and item_from_list[0]==n:
            result = True
        else:
            result = False
            break
        n+= 1
    if expected == result:
        return True
    else:
        return False

g = test_my_enumerate(['f','g','h'],[(0,'f'),(1,'g'),(2,'h')],True)
k = test_my_enumerate(['f','g','h'],[(0,'f'),(1,'h'),(2,'h')],False) 

Here you can see the test code in action

note: I don't think this is the most elegant or even the complete method for testing the algorithm, but its the best I could come up with.

RebeccaJillianBeattie commented 2 years ago

enumerate function

chloeppd commented 2 years ago
Screenshot 2021-11-02 at 12 02 51 PM
CarmenSantaniello commented 2 years ago
def test_my_enumerate(input_list, expected):
    result = my_enumerate(input_list)
    if expected == result:
        return True 
    else:
        return False

my_list = ["Gryffindor", "Hufflepuff", "Ravenclaw", "Slytherin"]

def my_enumerate(input_list):
    output_list = list()
    for item in input_list:
        my_tuple = (input_list.index(item), item)
        output_list.append(my_tuple)
    return output_list

print(test_my_enumerate(my_list, [(0, "Gryffindor"), (1, "Hufflepuff"), (2, "Ravenclaw"), (3, "Slytherin")]))
print(my_enumerate(my_list))

It returns:


True
[(0, 'Gryffindor'), (1, 'Hufflepuff'), (2, 'Ravenclaw'), (3, 'Slytherin')]
federicabonifazi commented 2 years ago
def test_my_enumerate(input_list, expected):
    result=my_enumerate(input_list)
    if expected == result:
        return True
    else:
        return False

def my_enumerate(input_list):
    enumerated_list = list()
    for item in input_list:
        enumerated_list.append ((input_list.index(item), item))
    return enumerated_list

print (test_my_enumerate(["a", "b", "c", "d"], [(0,"a"), (1,"b"), (2,"c"), (3,"d")]))
olgagolgan commented 2 years ago

image image

martasoricetti commented 2 years ago

image

ManueleVeggi commented 2 years ago
#Test case for the algorithm
def test_my_enumerate(input_list, expected_list):
    result = my_enumerate(input_list)
    if result == expected_list:
        return True
    else:
        return False

#Code of the algorithm
def my_enumerate(input_list):
    output_list = []
    for element in input_list:
        position = input_list.index(element)
        singletuple = (position, element)
        output_list.append(singletuple)     
    return output_list

#Test 1. Expect: T
in_list1 = list(["a","b","c"])
ex_list1 = list([(0, "a"), (1, "b"), (2, "c")])
print(test_my_enumerate(in_list1, ex_list1))

#Test 2. Expect: F
in_list2 = list(["a","b","d"])
ex_list2 = list([(0, "a"), (1, "b"), (2, "c")])
print(test_my_enumerate(in_list2, ex_list2))

#Test 3. Expect: F
in_list3 = list(["a","b","c"])
ex_list3 = list([(1, "a"), (2, "b"), (3, "c")])
print(test_my_enumerate(in_list3, ex_list3))

If the code is run, the results True, False, False: as a consequence, the code should be correct

OrsolaMBorrini commented 2 years ago
def test_my_enumerate(input_list, expected):
    result = my_enumerate(input_list)
    if result == expected:
        return True
    else:
        return False

def my_enumerate(input_list):
    result = list()
    for item in input_list:
        my_tuple = (input_list.index(item),item)
        result.append(my_tuple)
    return result

# Test 1
example_list = ["Alpha","Gamma","Beta"]
example_expected = [(0,"Alpha"),(1,"Gamma"),(2,"Beta")]
print(test_my_enumerate(example_list,example_expected)) # It should return True

print(my_enumerate(example_list))
# This correctly returns [(0, "Alpha"), (1, "Gamma"), (2, "Beta")]

# Test 2
example_list2 = ["Long John Silver", "Flint", "Jim Hawkins"]
example_expected2 = [(0,"Long John Silver"), (1,"Flint")]
print(test_my_enumerate(example_list2,example_expected2)) # It should return False, as one item is missing
tommasobattisti commented 2 years ago
def test_my_enumerate(input_list, expected):
    result = my_enumerate(input_list)
    if result == expected:
        return True
    else:
        return False

def my_enumerate(input_list):
    output_p_list = []
    for i in input_list:
        output_p_list.append((input_list.index(i), i))
    return output_p_list

print(test_my_enumerate(['a', 'b', 'c', 'd'],[(0, 'a'), (1, 'b'), (2, 'c'), (3, 'd')]))
print(test_my_enumerate(['red', 'purple', 'black', 'green'],[(0, 'red'), (1, 'purple'), (2, 'black'), (3, 'green')]))
MaddaGh commented 2 years ago

me_en

NoraPs commented 2 years ago

Cattura 2

katya-avem commented 2 years ago

image

AnastasiyaSopyryaeva commented 2 years ago

Task_3

def testing(input_list, expected):
    result = my_enumerate(input_list)
    if result == expected:
        return True
    else:
        return False

def my_enumerate(input_list):
    output = []
    for item in input_list:
        output.append((input_list.index(item), item))
    return output

print(testing(['a', 'b', 'c'], [(0, 'a'), (1, 'b'), (2, "c")]))
print(testing(['Italy', 'Spain', 'Germany', 'Norway'], [(0, 'Italy'), (1, 'Spain'), (2, 'Norway'), (3, 'Germany')]))

Returns True False

giorgimariachiara commented 2 years ago

def test_my_enumerate(input_list, expected): result = my_enumerate(input_list) if expected == result: return True else: return False

my_list = ("a", "b", "c")

def my_enumerate(input_list): output_list = list() for item in input_list: output_list.append((input_list.index(item), item)) return output_list

print(test_my_enumerate(my_list, [(0, "a"), (1, "b"), (2, "c")])) print(my_enumerate(my_list))

True [(0, 'a'), (1, 'b'), (2, 'c')]

angstigone commented 2 years ago
Schermata 2021-11-01 alle 17 21 46
elizastuglik commented 2 years ago

def test_my_enumerate(input_list, expected): result == my_enumerate(input_list) if result == expected: return true else: return false

def my_enumerate(input_list): output_list = list() for item in input_list: output_list.append(input_list.index(item), item))

return output_list

print(my_enumerate_test([1, 2, 3, 4], [(0, 1), (1,2), (2,3), (3,4)]))

Bianca-LM commented 2 years ago
def test_my_enumerate(input_list, expected): 
    result = my_enumerate(input_list)
    if expected == result: 
        return True
    else: 
        return False

from collections import deque

def my_enumerate(input_list): 
    result = list ()
    a = 0
    for item in input_list: 
        each_item = (a, item)
        result.append(each_item)
        a += 1
    return result

print (test_my_enumerate(["Qui", "Quo", "Qua"], [(0, "Qui"), (1, "Quo"), (2, "Qua")]))
essepuntato commented 2 years ago

Hi all,

Just a few general and specific comments:

AmeliaLamargese commented 2 years ago
def test_my_enumerate(input_list, expected):
    result = my_enumerate(input_list)
    if result == expected:
        return True
    else:
        return False

def my_enumerate(input_list):
    enum_list = list()
    for position in range(len(input_list)):
        enum_list.append(position, input_list[position])
    return enum_list 

print(test_my_enumerate([], []))   
print(test_my_enumerate(["ciao", "hello", "salut"], [(0, "ciao"), (1, "hello"), (2, "salut")])) 
print(test_my_enumerate([1, 2, 3], [(0, 1), (1, 2), (2, 3)])) 
print(test_my_enumerate(["ciao", 1, "hello", 2], [(0, "ciao"), (1, 1), (2, "hello"), (3, 2)])) 
OrsolaMBorrini commented 2 years ago

Hello, @essepuntato

I tried to run my algorithm with the input list ['a', 'a', 'b', 'a'] and of course I found out it didn't really work. The output was: [(0, 'a'), (0, 'a'), (2, 'b'), (0, 'a')] when it should have been [(0,'a'),(1,'a'),(2,'b'),(3,'a')].

At first I thought to delete the item analysed at every iteration, but again, it did not seem to work, as the other elements shifted (changing all the indexes). The output was: [(0, 'a'), (1, 'b')].

I found this solution, that seems to work! I thought to "scroll" through the list using the index of each item, initialising it at value 0. The procedure is:

  1. I create the result list (empty)
  2. I create a new variable for the index and I initialise it to 0 (as I start to scroll through the list starting from the first item, with index 0)
  3. I use a while instruction with condition (index < length of the input list) and in which I:
    • Create a new variable with value the value of the element with that index
    • Create a tuple (index, value of the element with that index)
    • Add the tuple to my result list
    • "Update" the value of the index +1 (modifying the condition of the while instruction)
  4. Return the result list

I think it's much easier to understand by looking at the code! I really hope I made no mistakes...

def new_my_enumerate(input_list):
    result = list()
    i = 0
    while i < len(input_list):
        item = input_list[i]
        my_tuple = (i,item)
        result.append(my_tuple)
        i += 1
    return result

example_list = ['Alpha','Gamma','Beta']
new_list = ['a', 'a', 'b', 'a']
print(new_my_enumerate(example_list)) #This returns [(0, 'Alpha'), (1, 'Gamma'), (2, 'Beta')]
print(new_my_enumerate(new_list)) #This returns [(0, 'a'), (1, 'a'), (2, 'b'), (3, 'a')]
sarabecchi commented 2 years ago

esercizio 3

OUTPUT:

esercizio 3 - output

from collections import deque

def my_enumerate(input_list):
    result = deque()

    for i in range(len(input_list)):
        #print(range(len(input_list)))
        #print(i)
        #print(input_list[i])
        result.append((i, input_list[i]))
    return result

def test_my_enumerate(input_list, expected):
    result = my_enumerate(input_list)
    if result == expected:
        return True
    else:
        return False

print(test_my_enumerate([0, 1, 2, 3], deque([(0, 0), (1, 1), (2, 2), (3, 3)])))
print(test_my_enumerate([], deque([])))
print(test_my_enumerate(["a"], deque([(0, "a")])))