Open essepuntato opened 10 months ago
def test_my_reversed(input_list, expected):
result = my_reversed(input_list)
if result == expected:
return True
else:
return False
def my_reversed(input_list):
reversed_list = list()
n = len(input_list)
while n > 0:
reversed_list.append(input_list[n - 1])
n = n-1
return reversed_list
print(test_my_reversed(list(["a", "b", "c"]), list(["c", "b", "a"])))
print(test_my_reversed(list(["a", "b", "c", 123, "test"]), list(["test", 123, "c", "b", "a"])))
print(test_my_reversed(list(["a", "b", "c"]), list(["d", 15, "a"])))
def test_my_reversed(input_list, expected):
if my_reversed(input_list) == expected:
return True
else:
return False
def my_reversed(input_list):
reversed_list = input_list[::-1]
return reversed_list
print(test_my_reversed(list([0, 1, 2, 3]), list([3, 2, 1, 0])))
Otherwise:
def test_my_reversed(input_list, expected):
if my_reversed(input_list) == expected:
return True
else:
return False
def my_reversed(input_list):
rev_list = list()
index_list = range(1, len(input_list) + 1)
for i in index_list:
rev_list.append(input_list[-i])
return rev_list
print(test_my_reversed(list([1, 2, 3, 4]), list([4, 3, 2, 1])))
# Test case for the algorithm
def test_my_reversed(input_list,expected):
result = my_reversed(input_list)
if expected == result:
return True
else:
return False
# Code of the algorithm
def my_reversed(input_list):
reversed_list = [] # A new empty list where to store the result
# List comprehension that iters through index number and appends the negative-1
# indexed item to the output list (e.g. for index 0 the -1 indexed (last) item)
reversed_list = [input_list[0-(i+1)] for i in range(len(input_list))]
return reversed_list
print(test_my_reversed([1, 2, 3, 4], [4, 3, 2, 1])) # True
print(test_my_reversed(["a", "b", "c", "d"], ["d", "c", "b", "a"])) # True
print(test_my_reversed([4, 3, 2, 1], [1, 2, 3, 4])) # True
print(test_my_reversed([0, 1, 0, 1, 1], [1, 1, 0, 1, 0])) # True
print(test_my_reversed([1], [1])) # True
print(test_my_reversed([], [])) # True
def my_reversed(input_list):
reversed_list = list()
i = len(input_list)
while i > 0:
reversed_list.append(input_list[i-1])
i-=1
return reversed_list
def test(input,expectation):
if input == expectation:
return True
else:
return False
dhdk = ["comp-think","tram","sedt","tesr"]
reversed_dhdk = dhdk[::-1]
print(test(my_reversed(dhdk),reversed_dhdk))
def my_reversed(input_list):
reversed_list = []
for item in input_list:
reversed_list.insert(0, item)
return reversed_list
# test function
def test_my_reversed(input_list, expected):
if my_reversed(input_list) == expected:
return True
else:
return False
# test cases
test_my_reversed([1, 2, 3, 4], [4, 3, 2, 1])
test_my_reversed([], [])
test_my_reversed([3, 2, 1], [1, 2, 3])
test_my_reversed(['Hey'], ['Hey'])
def test_my_reversed(input_list, expected):
result = my_reversed(input_list)
if expected == result:
return True
else:
return False
def my_reversed(input_list):
reversed_list = []
for item in input_list:
reversed_list.insert(0, item)
return reversed_list
print(test_my_reversed([1, 2, 3, 4], [4, 3, 2, 1]))
print(test_my_reversed(["a", "b", "c", "d"], ["d", "c", "b", "a"]))
print(test_my_reversed([0], [0]))
def test_my_reversed(input_list, expected):
result = my_reversed(input_list)
if result == expected:
return True
else:
return False
def my_reversed(input_list):
result_list = []
for item in input_list:
result_list.insert(0, item)
return result_list
print(test_my_reversed(([0, 1, 2, 3]), ([3, 2, 1, 0])))
# test function
def test_my_reverse(reverse_number, expected):
result = my_reverse(reverse_number)
if result == expected:
return True
else:
return False
# function
def my_reverse(reverse_number):
reverse_list = list()
n = 0
while reverse_number > n:
reverse_list.append(n)
n += 1
return reverse_list
# three tests run
print(test_my_reverse(-1, ([0, 1, 2])))
print(test_my_reverse(2, ([0, 1, 2])))
print(test_my_reverse(3, ([0, 1, 2])))
1° output: False 2nd output: False 3rd output: True
def test_my_reversed(input_list, expected):
result = my_reversed(input_list)
return result == expected
def my_reversed(input_list):
res = []
for i in range(1, len(input_list)+1):
res.append(input_list[-i])
return res
print(test_my_reversed(['a', 'b', 'c', 'd'], ['d', 'c', 'b', 'a']))
print(test_my_reversed([0], [0]))
from collections import deque
def test_my_reversed(input_list, expected):
result = my_reversed(input_list)
if result == expected:
return True
else:
return False
def my_reversed(input_list):
my_stack = deque()
my_stack.extend(input_list)
copied_stack = my_stack.copy()
reversed_list = list()
for item in my_stack:
item = copied_stack.pop()
reversed_list.append(item)
return reversed_list
print(test_my_reversed(["Batman", "Superman", "Flash", "Wonder Woman", "Joker", "Cyborg"], ['Cyborg', 'Joker', 'Wonder Woman', 'Flash', 'Superman', 'Batman']))
print(test_my_reversed(["Batman", "Superman", "Batman", "Flash"], ['Flash', 'Batman', 'Superman', 'Batman']))
print(test_my_reversed(["Batman"], ["Batman"]))
print(test_my_reversed([], []))
def test_my_reversed(input_list, expected):
result = my_reversed(input_list)
if result == expected:
return True
else:
return False
def my_reversed(input_list):
output_list = list()
# n is the number of items in the input_list that is the same for the output_list
# and n is also used for indexing items
n = len(input_list)
for item in input_list:
# appending to the first position of the output_list
# the item that stands in the last position of the input_list
output_list.append(input_list[n-1])
n -= 1
return output_list
print(test_my_reversed([],[]))
print(test_my_reversed([0,1],[1,0]))
print(test_my_reversed([6,7,8,9],[9,8,7,6]))
Write in Python the function
def my_reversed(input_list)
, which behaves like the built-in functionreversed()
introduced in Section "Insertion sort" and returns a proper list, and accompany the function with the related test case. It is not possible to use the built-in functionreversed()
in the implementation.