Closed congr closed 5 years ago
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public int[] findMode(TreeNode root) {
Map<Integer, Integer> map = new HashMap();
List<Integer> list = new ArrayList();
preorder(root, map);
for (int key : map.keySet()) {
if (map.get(key) == max) list.add(key);
}
int[] res = new int[list.size()];
int i = 0;
for (int n : list) res[i++] = n;
return res;
}
int max;
void preorder(TreeNode root, Map<Integer, Integer> map) {
if (root == null) return;
max = Math.max(max, map.merge(root.val, 1, Integer::sum));
preorder(root.left, map);
preorder(root.right, map);
}
}
Follow up: Could you do that without using any extra space? (Assume that the implicit stack space incurred due to recursion does not count).