Closed shomjm closed 1 year ago
This is because your chiral template specifies that the carbon with atom map 2 has a hydrogen in the reactants side and, when copied over to the product, is left implicit. This leads to a valence issue, which you can see if you install rdchiral from source with python setup.py install
and set PLEVEL = 99
in the header of utils.py
:
[O:1]=[CH:2]([CH3:3])[CH2:4][CH3:5], Explicit valence for atom # 1 C, 5, is greater than permitted
You can fix this by correcting your chiral template to the following:
"[OH:1][C@H:2]([C:3])[C:4]>>[O:1]=[CH0:2]([C:3])[C:4]"
Thank you for your reply. Your template include "CH0" worked well!
I want to write template of chiral alchol to ketone. In the case of not chiral alchol, template
"[Oh:1][C:2]([C:3])[C:4]>>[O:1]=[C:2]([C:3])[C:4]"
worked well for reactant"OC(C)CC"
: then it gave['CCC(C)=O']
. But in the case of chiral alchol, template"[Oh:1][C@H:2]([C:3])[C:4]>>[O:1]=[C:2]([C:3])[C:4]"
didn't work for reactant"O[C@H](C)CC"
: then it gave[]
. How I write template for chiral alchol?