Closed richardhj closed 5 years ago
$varInput might be null, however, the code is constructed to expect an array.
$varInput
null
$varInput[$i]
\array_keys($varInput)
Invalid argument supplied for foreach()
count($varInput)
$varInputmight benull, however, the code is constructed to expect an array.$varInput[$i]\array_keys($varInput)--> results inInvalid argument supplied for foreach()count($varInput)--> provokes error since PHP 7.2