Closed pgkirsch closed 3 years ago
Why not fit z/x^0.5=u?
On Dec 27, 2016 17:07, "pgkirsch" notifications@github.com wrote:
This might sound like a strange request, and I haven't really thought about how feasible it is, but it would be nice if a user could specify the power on a certain independent variable based on a priori knowledge of the underlying relationships.
For example, if I am fitting a function, z = f(x, y) and I know that z should go with x^0.5, it would be nice to "fix" that part of the regression, so I end up with something like z = 4.58x^0.5y^0.234.
— You are receiving this because you are subscribed to this thread. Reply to this email directly, view it on GitHub https://github.com/hoburg/gpfit/issues/62, or mute the thread https://github.com/notifications/unsubscribe-auth/ABagGGdAh5g32Zqy_rqdKvjMEwkzdSQuks5rMbZHgaJpZM4LWmeV .
This might sound like a strange request, and I haven't really thought about how feasible it is, but it would be nice if a user could specify the power on a certain independent variable based on a priori knowledge of the underlying relationships.
For example, if I am fitting a function,
z = f(x, y)
and I know that z should go withx^0.5
, it would be nice to "fix" that part of the regression, so I end up with something likez = 4.58*x^0.5*y^0.234
.