Closed erramidad123 closed 4 months ago
a : integer > 1 : [2,4,5,6,7,8....] n : integer > 1
exp : const expr = ce.parse("\frac{x}{3}");
for (const x = 0; x < 1; x += 0.01) { ce.assign('x', x); console.log(f(${x}) = ${expr.value}); // this will be constant all time . }
f(${x}) = ${expr.value}
It seems to work using top of tree. I believe this is a duplicate of #150.
a : integer > 1 : [2,4,5,6,7,8....] n : integer > 1
exp : const expr = ce.parse("\frac{x}{3}");
for (const x = 0; x < 1; x += 0.01) { ce.assign('x', x); console.log(
f(${x}) = ${expr.value}
); // this will be constant all time . }