when I throw an exception in the labmda expression of hgetall, it goes to line 70 (in the file thread_pool.cpp).
Continue debugging, programm will pause when excute to line 124 (in the file thread_pool.cpp).
So, how can i get the exception out of the lambda expression?
code:
when I throw an exception in the labmda expression of hgetall, it goes to line 70 (in the file thread_pool.cpp). Continue debugging, programm will pause when excute to line 124 (in the file thread_pool.cpp).
So, how can i get the exception out of the lambda expression?
platform: Windows10, VS2019-16.7.5
Thank you!