Open Jay413191 opened 2 years ago
如下,后端不会解析传过去的参数,都并到第一个去了
前端程序 let url = "api/V_OrderShippingDetail/getNoShippingOrderDetailQty?OrderNo="+formData.mainData.OrderNo+"?SNo=" +x.OrderSNo this.http.get(url, {}, true).then((result) => { let row = result; });
后端程序
?改为&就可以了let url = "api/V_OrderShippingDetail/getNoShippingOrderDetailQty?OrderNo="+formData.mainData.OrderNo+"&SNo=" +x.OrderSNo
可以了, 谢谢大大!!
如下,后端不会解析传过去的参数,都并到第一个去了
前端程序 let url = "api/V_OrderShippingDetail/getNoShippingOrderDetailQty?OrderNo="+formData.mainData.OrderNo+"?SNo=" +x.OrderSNo this.http.get(url, {}, true).then((result) => { let row = result; });
后端程序![image](https://user-images.githubusercontent.com/81396265/170678966-6530ca41-1fa4-41cf-890d-62e5969c0a97.png)