Closed hmf closed 10 months ago
The trick of using a "reference shape" also does not work perfectly. The final image tries to show as much of the 2 shapes as possible. In doing so it shifts the frame shape by several pixels (5 pixels in the example below).
Is their any "magic" call I can use to ensure a shape is never clipped?
Here is the output I get (I expect the origin to be at the bottom left corner of the frame):
Here are the code snippets:
val width = 100
val height = 100
def frameSquare() =
val picture = Picture.rectangle(width, height)
.strokeColor(Color.black)
.margin(0)
// .originAt(-width/2, -height/2)
.originAt(Landmark.bottomLeft)
.at(0,0)
.debug
picture
def randomSquare(frame: Picture[Unit]) =
frame.on(
Picture.square(20)
.strokeColor(Color.black)
.margin(0)
.originAt(0, 0)
.at(0,0)
.debug
)
val framePicture = frameSquare()
val picture = randomSquare(frame = framePicture )
val frame = Frame.default.withSize(width , height).withBackground(Color.white)
val out1 = os.pwd / "circle.png"
println(out1.toIO)
picture.write[Png](out1.toIO, frame)
TIA
I think you want withCenterAtOrigin
: https://www.javadoc.io/doc/org.creativescala/doodle-docs_3/latest/doodle/java2d/effect/Frame.html
This sets the origin of the frame to the origin of the Picture
. From that you can do layout in terms of absolute coordinates.
@noelwelsh Worked perfectly. Thank you.
Great!
I need to place shapes in random spots of a
Frame
of fixed width. I have read the documentation and it seems that all layout operations are relative to each shape's bounding box. In addition to this, a single shape is always placed with its origin in the center of thePicture
's frame.Is their any way I can place a shape in a fixed (x,y) within a frame without using a reference shape (size of frame, no margin) ?
TIA