Closed crowlogic closed 5 months ago
$$ Kn(x, y) = \sum{k=0}^{n} p_k(x) p_k(y) $$
actually.. I found a better way to solve it.. dont need this for now. woop
$$ Kn(x, y) = \sum{k=0}^{n} p_k(x) p_k(y) $$