Howdy. I've run into a problem on a MySQL server I'd like to use invoke-mysqlquery for. Using a login that involves a semicolon or backtick appears to cause errors. On the backtick I get a simple 'access denied', though I can work around it by adding 1 extra backtick (which probably means you'd need 1 extra backtick per actual backtick). On the one with multiple special characters, I get the below error, probably related to the semicolon in the password, but could be the equals sign.
I'm unsure how the connection string creator handles it, but I would expect you could put the password in double quotes and have it work.
I get the following error. (note that it shows the partial password, which shows that it's due to it misinterpreting the semicolon):
VERBOSE: Using the following connection string: Data Source=localhost;Initial Catalog=INFORMATION_SCHEMA;User ID=abcdefgh;Password=xxxxxxxxxx;adbgw&;
VERBOSE: Opening connection.
Invoke-MySqlQuery : Format of the initialization string does not conform to specification starting at index 95.
At line:14 char:12
+ $result = (Invoke-MySqlQuery -sql $query -Database $db -Credential $mycreds -Ver ...
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : NotSpecified: (:) [Invoke-MySqlQuery], ArgumentException
+ FullyQualifiedErrorId : System.ArgumentException,InvokeQuery.InvokeMySqlQuery
Howdy. I've run into a problem on a MySQL server I'd like to use invoke-mysqlquery for. Using a login that involves a semicolon or backtick appears to cause errors. On the backtick I get a simple 'access denied', though I can work around it by adding 1 extra backtick (which probably means you'd need 1 extra backtick per actual backtick). On the one with multiple special characters, I get the below error, probably related to the semicolon in the password, but could be the equals sign.
I'm unsure how the connection string creator handles it, but I would expect you could put the password in double quotes and have it work.
Thanks in advance!
I get the following error. (note that it shows the partial password, which shows that it's due to it misinterpreting the semicolon):