Closed reddibhatini closed 4 years ago
I have a Method waiting on a pull request that lets you execute an MDX query against a dimension. A complimentary function that saves it as a subset would be nice.
Thanks,
Ryan Clapp
From: reddibhatini notifications@github.com Sent: Monday, January 27, 2020 8:45 AM To: cubewise-code/tm1py tm1py@noreply.github.com Cc: Subscribed subscribed@noreply.github.com Subject: [cubewise-code/tm1py] How to Create subset using mdx string (#206)
Hello,
Is there a way to create a subset using MDX? Could not able to find a method for this.
Thank you
— You are receiving this because you are subscribed to this thread. Reply to this email directly, view it on GitHubhttps://github.com/cubewise-code/tm1py/issues/206?email_source=notifications&email_token=AEK7GZQ4IQ43FIR5N6MDB3LQ74FPBA5CNFSM4KMEOPN2YY3PNVWWK3TUL52HS4DFUVEXG43VMWVGG33NNVSW45C7NFSM4II7I3EQ, or unsubscribehttps://github.com/notifications/unsubscribe-auth/AEK7GZXUVCHUEZS3CUNWMR3Q74FPBANCNFSM4KMEOPNQ.
Hi @reddibhatini, here is a sample:
with TM1Service(address=ADDRESS, port=PORT, user=USER, password=PASSWORD, ssl=SSL) as tm1:
dimension_name = "}Clients"
expr = "{TM1SubsetAll([}Clients])}"
subset = Subset(
subset_name="All Clients",
dimension_name="}Clients",
hierarchy_name="}Clients",
expression=expr)
if not tm1.dimensions.hierarchies.subsets.exists(
subset_name=subset.name,
dimension_name=dimension_name,
hierarchy_name=dimension_name,
private=False):
tm1.dimensions.hierarchies.subsets.create(subset, private=False)
else:
tm1.dimensions.hierarchies.subsets.update(subset, private=False)
@rclapp Thanks for the MR. Much appreciated! Will look into it in more depth on the weekend. I agree. It would be nice to have a simplified method to create a subset from mdx with just one call.
@rclapp @MariusWirtz Thank you. That was helpful. Yeah. I was looking for method call to create subset by mdx.
Hello,
Is there a way to create a subset using MDX? Could not able to find a method for this.
Thank you